CGL Tier-2 Quant Questions With Detailed Solutions
Dear students, you know that QUANT is a part of getting points and every chapter is important. Therefore, we are providing 15 questions of quant. Solve all these quizzes every day so that you can improve your accuracy and speed.We also provide lots of quant questions. So you can practice that chapter which takes more time to solve the questions.
Q3. Two circles with centre A and B and radius 2 units touch each other externally at ‘C’. A third circle with centre ‘C’ and radius ‘2’ units meets other two at D and E. Then the area of the quadrilateral ABDE is
(a) 2√2 sq. units
(b) 3√3 sq. units
(c) 3√2 sq. units
(d) 2√3 sq. units
Q4. A shopkeeper earns a profit of 12% on selling a book at 10% discount on printed price. The ratio of the cost price to printed price of the book is
(a) 45 : 56
(b) 50 : 61
(c) 90 : 974
(d) 99 : 125
Q5. A dealer purchased a washing machine for Rs. 7,660. After allowing a discount of 12% on its marked price, he still gains 10%. Find the marked price of the washing machine.
(a) Rs. 9,575
(b) Rs. 8,426
(c) Rs. 8,246
(d) Rs. 9,755
Q6. A saleable article passes successively in the hands of three traders. Each trader sold it further at a gain of 25% of the cost price. If the last trader sold it for Rs. 250 then what was the cost price for the first trader?
(a) Rs. 128
(b) Rs. 150
(c) Rs. 192
(d) Rs. 200
Q7. Rs. 6,000 becomes Rs. 7,200 in 4 years. If the rate becomes 1.5 times of itself, the amount of the same principal in 5 years will be
(a) Rs. 8,000
(b) Rs. 8,250
(c) Rs. 9,250
(d) Rs. 9,000
Q8. Two alloys contain tin and iron in the ratio of 1 : 2 and 2 : 3. If the two alloys are mixed in the proportion of 3 : 4 respectively (by weight), the ratio of tin and iron in the newly formed alloy is:-
(a) 14 : 25
(b) 10 : 21
(c) 12 : 23
(d) 13 : 22
Q9. Tom is chasing Jerry. In the same interval of time Tom jumps 8 times while Jerry jumps 6 times. But the distance covered by Tom in 7 jumps in equal to the distance covered by Jerry in 5 jumps. The ratio of speed of Tom and Jerry is
(a) 48 : 35
(b) 28 : 15
(c) 24 : 20
(d) 20 : 21
Q10. A labourer was appointed by a contractor on the condition he would be paid Rs. 75 for each day of his work but would be, fined at the rate of Rs. 15 per day for his absent. After 20 days, the contractor paid the labourer Rs. 1140. The number of days the labourer absented from work was
(a) 3 days
(b) 5 days
(c) 4 days
(d) 2 days
Q11. A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
(a) 10 days
(b) 12 days
(c) 15 days
(d) 20 days
Q12. A boy and girl together fill a cistern with water. The boy pours 4 litres of water every 3 minutes and the girl pours 3 litres of water every 4 minutes. How much time will it take to fill 100 litres of water in the cistern?
(a) 36 minutes
(b) 42 minutes
(c) 48 minutes
(d) 44 minutes
Q13. A train 100m long is running at the speed of 30 km/hr. The time (in second) in which it passes a man standing near the railway line is:
(a) 10
(b) 11
(c) 12
(d) 15
S13. Ans.(c)
Sol. Speed = 30 km/hr = 30 × 5/18 m/sec.
= 25/3 m/sec
So, time = D/S=100/(25/3) = 12 sec.
Q14. A train crosses a pole in 15 seconds and a platform 100 metres long in 25 seconds. Length of train (in metres) is
(a) 50
(b) 100
(c) 150
(d) 200
S14. Ans.(c)
Sol. We can inferred that train crosses only platform not its length in 25 – 15 = 10 second
⇒ Speed of the train = (100 metres)/(10 sec) = 10 m/s
∵ Train crosses the pole in 15 seconds and we know when train crosses a pole/tree/man this case it covers the equal distance of its length.
Therefore,
Length of train = 15 × 10
= 150 metres.
Q15. Two trains travel in the same direction at the speed of 56 km/hr and 29 km/hr. respectively. The faster train passes a man in the slower train in 10 seconds. The length of the faster train (in metres) is
(a) 100
(b) 80
(c) 75
(d) 120
S15. Ans.(c)
Sol. When a faster train crosses the man who sits in the other train, on that time faster train covers the distance equal to its length but the relative speed (opposite/same direction) is considered in respect of man.
Relative speed of the trains = (56 – 29) km/h = 27 km/h
Length of faster train = Distance covered by faster train in 10 second with Relative speed of 27 km/h
= 27 km/h × 10 sec.
= 27 × 5/18 × 10 m.
= 75 metres
